A drop of solution `("volume" =0.05 mL)` contains `3xx10^(-2)` mole of `H^(+)`. If the rate constant of disappearance of `H^(+)` is `1.0xx10^(2) mol litre^(-1) minute^(-1)`. How long (in minutes) will it take to disappear all the `H^(+)` ions?

A drop of solution `("volume" =0.05 mL)` contains `3xx10^(-2)` mole of

1.	A drop of solution `("volume" =0.05 mL)` contains `3xx10^(-2)` mole of `H^(+)`. If the rate constant of disappearance of `H^(+)` is `1.0xx10^(2) mol litre^(-1) minute^(-1)`. How long (in minutes) will it take to disappear all the `H^(+)` ions?
Answer» Correct Answer - 6 `0.05 mL` has `3xx10^(-2)` mole of `H^(+)` `1000 mL` has `(3xx10^(-2)xx1000)/(0.05)=600` mole `H^(+)` `K=X/t` (zero order, follow unit of K) `t=600/(1xx10^(2))=6 minute`

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A drop of solution `("volume" =0.05 mL)` contains `3xx10^(-2)` mole of `H^(+)`. If the rate constant of disappearance of `H^(+)` is `1.0xx10^(2) mol litre^(-1) minute^(-1)`. How long (in minutes) will it take to disappear all the `H^(+)` ions?

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