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A drug is given intravenously and drug concentrations in blood measured at 1 and 4 hour are 26 and `18mu g//mL`. What is the half-line of drug and at what time will the level decreases to `10mu g//mL` |
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Answer» `t = (2.303)/(lambda) log (N_(0))/(N)` `t = 1 hr, N = 26 mu g//mL` `:. 1 = (2.303)/(lambda) log (N_(0))/(26)` ...(i) `t = 4hr, N = 18 mug//mL` `:. 4 = (2.303)/(lambda) log (N_(0))/(18)` ....(ii) `:.` By eqn. (i) and (ii) `lambda = 0.123 hr^(-1)` and `N_(0) = 29.40 mug//mL` `:. t_(1//2) = (0.693)/(lambda) = (0.693)/(0.123) = 5.63 hr` Now `t = (2.303)/(0.123) log (29.40)/(10) = 8.77 hr` |
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