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A drunkard waking in a barrow lane takes ` 5` steps forward and `3` steps backward, followed again `5` steps forward and `3` steps backward, and so on. Each step is ` 1 m`long and requires 1 s. Determine how long the drunkard takes to fall in a pit ` 13 m` away from start.

Answer» Distance of the pit from the start `=13-5=8m`
Time taken to move first `5m=5sec`
5 steps (i.e., 5m) forward and 3 steps (i.e., 3m) backward means that net distance moved `=5-3=2m`
and time taken during this process `=5+3=8sec`
`:.` Time taken in moving `8m=(8xx8)/(2)=32sec`
`:.` Total time to fall in the pit`=32+5=37sec`


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