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A drunkard waking in a barrow lane takes ` 5` steps forward and `3` steps backward, followed again `5` steps forward and `3` steps backward, and so on. Each step is ` 1 m`long and requires 1 s. Determine how long the drunkard takes to fall in a pit ` 13 m` away from start. |
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Answer» Distance of the pit from the start `=13-5=8m` Time taken to move first `5m=5sec` 5 steps (i.e., 5m) forward and 3 steps (i.e., 3m) backward means that net distance moved `=5-3=2m` and time taken during this process `=5+3=8sec` `:.` Time taken in moving `8m=(8xx8)/(2)=32sec` `:.` Total time to fall in the pit`=32+5=37sec` |
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