1.

(a)Explain with the help of a labelled diagram an acitivity for the verification of law of conservation of mass. (b)Find the number of atoms present in 100g of sodium and 100g of iron. (Given that Na=23u, Fe=56u,N_(0)=6.022xx10^(23) per mole)

Answer»

Solution :(a) For ANSWER, CONSULT of sodium =3.1
(b)Gram atomic mass of sodium=23g
No. of atoms in 23g of sodium=`N_(A)=6.022xx10^(23)`
`"No. of atoms in 100g of sodium"=6.022xx10^(23)XX((100g))/((23g))=2.618xx10"atoms"`
Gram atomic mass of iron=100g
No. of atoms in 56G of iron= `N_(A)=6.022xx10^(23)`
No. of atoms in 100g of iron `=6.022xx10^(23)xx((100g))/((56g))=1.075xx10^(24)"atoms"`


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