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A factory has produced 6750 pieces of toys out of which 12% were found to be defective. Out of the remaining, if 15% were not sold, how many toys were sold? (a) 4927 (b) 5049 (c) 5159 (d) 5909 |
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Answer» Answer - B) 5049 Number of defective toys = 6750 x (12/100) = 810 Number of good toys = 6750-810 = 5940 Number of toys not sold = 5940 x (15/100) = 891 Therefore, number of toys sold = 5940-891 = 5049 Hope this helps you |
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