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InterviewSolution
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A fair coin is tossed 100 times. The probability of getting tails anodd number of times is`1//2`b. `1//8`c. `3//8`d. none of theseA. `1//2`B. `1//8`C. `3//8`D. none of these |
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Answer» Correct Answer - A Let X denote the number of tails. Then X is a binomial variate with parameters `n=100 and p =1//2` such that `P(X=r)=.^100C_(r)((1)/(2))^100,r=0,1,2,...., 100`. `therefore` Required Probability `=P(X=1)+P(X=3)+......+P(X=99)` `=((1)/(2))^100{.^100C_(1)+.^100C_(3)+....+.^100C_(99)}=(1)/(2^100)xx2^99=(1)/(2)`. |
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