1.

A fair coin is tossed for 10 times, what is the probability of getting 2 heads

Answer»

Probability of getting head in tossing a coin is p =1/2 and probability of not getting a head is also q=1/2 in one trial. 

The probablprob distribution is binomial. So probability of getting r heads in n trial is 

P(x = r) = nCr×p^r×q(^(n-r)

So probability of getting 2 heads in 10 trial is

P (x=2) = 10C2×(1/2)^2(1/2)^10

 =45/2^10 =45/1024



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