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InterviewSolution
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A feather is dropped on the moon from aheight of 1.40 meters. The acceleration ogravity on the moon is 1.67 m/s2.Determine the time for the feather to falto the surface of the moon. |
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Answer» Given: vi = 0 m/s d = -1.40 m a = -1.67 m/s2 Find: t = ??d = vi*t + 0.5*a*t2-1.40 m = (0 m/s)*(t)+ 0.5*(-1.67 m/s2)*(t)2 -1.40 m = 0+ (-0.835 m/s2)*(t)2 (-1.40 m)/(-0.835 m/s2) = t2 1.68 s2 = t2 t = 1.29 s |
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