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A film is held on a ring of area 0.05 `m^(2)` of liquid of surface tension 0.05 N/m then the surface energy isA. 25 JB. `0.01` JC. `0.5` JD. `25xx10^(-4)`J |
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Answer» Correct Answer - D Surface energy , `= 4piR^(2)T` ` = 0.05 xx 0.05 ` N/m ` = 25 xx10^(-4)` J |
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