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A first order of reaction is `75%` complete in `18` minute. What is the half-life period for the reaction ? |
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Answer» Correct Answer - 9 `K=2.303/t"log"a/((a-x))` `K=2.303/18"log"100/((100-75))=2.303/18xx"log" 4` `=7.7xx10^(-2)` Now `t_(1//2)=0.693/K=0.693/(0.77xx10^(-2))=9 min` |
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