1.

A first order of reaction is `75%` complete in `18` minute. What is the half-life period for the reaction ?

Answer» Correct Answer - 9
`K=2.303/t"log"a/((a-x))`
`K=2.303/18"log"100/((100-75))=2.303/18xx"log" 4`
`=7.7xx10^(-2)`
Now `t_(1//2)=0.693/K=0.693/(0.77xx10^(-2))=9 min`


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