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A first order reaction has a rate constant `1.15xx10^(-3)s^(-1)`. How long will `5g` of this reactant take to reduce to `3g`` ?A. 444sB. 400sC. 528sD. 669s |
Answer» Correct Answer - A `t = (2.303)/(k) "log" ([R_(0)])/([R]) = (2.303)/(1.15 xx 10^(-3)) "log" (5)/(3)` `=2.00 xx 10^(3) log 1.667 = 2 xx 10^(3) xx 0.2219 = 444s` |
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