1.

A first order reaction has a rate constant of 0.0051 `min^(-1)`. If we begin with 0.10 M concentration of the reactant, What concentration of reactant will remain in solution after 3 hours?

Answer» For a first order reaction, `k=2.303/tloga/(a-x)`
k = 0.0051 `min^(-1)`, a-0.10M, t=3hr =`3 xx 60=180min`.
`loga/(a-x) = (k xx t)/(2.03) =((0.0051 min^(-1)) xx (180 min))/(2.303) = 0.3986`
`a/(a-x) = "antilog"(0.3986) = 2.053`
`(a-x) = a/(2.503) = (0.10M)/(2.503)= 0.039 M`


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