

InterviewSolution
Saved Bookmarks
1. |
A first order reaction in `75%` complete is 60 minutes. Find the half life of this reaction. |
Answer» Step I: Calculation of rate constant. `a=100% (a-x) = 25%, t=60 min`. for first order reaction, `k=(2.303)/k log a/(a-x) = (2.303)/(60"min") log 100/25` `=(2.303)/(60 "min") xx log4 = (2.303 xx 0.6020)/(60 min) = 0.0231 min^(-1)` Step II: Calculation or half life period `(t_(1//2))` `t_(1//2) = 0.693/k = (0.693)/(0.0231 min^(-1))=30 min` |
|