1.

A first order reaction is `75%` complete in 60 min. Find the half life period of the reaction?

Answer» Step I: Calculation of rate constant,
`a=100% (a-x) = 25%, t=60` min
for first order reaction,
`k=(2.303)/t log a/(a-x) = (2.303)/(a-x) log 100/25 = (2.303)/(60"min") xx log4 = (2.303 xx 0.6020)/(60 "min") = 0.0231 min^(-1)`
Step-II: Calculation of half life period `(t_(1//2))`
`t_(1//2) = 0.693/k = 0.693/(0.0231 min^(-1)) = 30` min.


Discussion

No Comment Found

Related InterviewSolutions