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A first order reaction takes 100 min for completion of 60 % of reaction ,The time eequired for completion of 90% of the reaction isA. `150 min `B. `200`minC. `220.9`minD. `246.6` min |
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Answer» Correct Answer - D For the order reaction ,`k=(2.303)/(t)log""(C_(0))/(C_(t))` Case I: `C_(0)=100 M,C_(t) =100 -60 =40, t= 100 min` `k=(2.303)/(100)xxlog""(100)/(40)` `k=(2.303xx0.3979)/(100)` case-II : `C_(0)=100 M,C_(t)=100-90=10M ` `t=(2.303)/(k) log""(100)/(10)` `=(2.303)/(k)` .... substituting K from I `=(2.303xx100)/(2.303xx0.3979)=245.6 min` |
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