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A first order reaction takes 40 minutes for `30%` decomposition. Calculate its half life period. |
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Answer» For the first order reaction, `k=2.303/k xx a/(a-x)` `a=100%, x=30%, (a-x) = (100-30) =70%,` t=40 min `a=100%, x=30%, (a-x)=(100-30)=70%`, t=40min `k =(2.303)/(40min)log 100/70 = 2.303/(40 min) xx 0.1549 = 0.00892 min^(-1)` `t_(1//2) = 0.693/k= 0.693/(0.00892 min^(-1)) = 77.7 min` |
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