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A follows first order reaction. `(A) rarr Product` The concentration of `A` changes form `0.1 M` to `0.025 M` in `40 min`. Find the rate of reaction of `A` when the concentration of `A` is `0.01 M`.A. (a) `3.47xx10^(-4) M//min`B. (b) `3.47xx10^(-5) M//min`C. (c ) `1.73xx10^(-4) M//min`D. (d) `1.73xx10^(-5) M//min` |
Answer» Correct Answer - a For the first order reaction `K=2.303/t"log"a/(a-x)` `a=0.1 M, a-x=0.025 M, t=40 min` `K=2.303/40"log"0.1/0.025` `=2.303/40"log"4=0.0347 min^(-1)` `[A] rarr` product Thus, rate=`K[A]` rate`=0.0347xx0.01 M min^(-1)` `=3.47xx10^(-4) M min^(-1)` |
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