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A force 20N acts for 40seconds on a body of mass 5 kg from rest a. Its initial momentum is _____________. b. Its final velocity is _____________. Now the force is withdrawn, d. Its displacement in the next 20 seconds is _____________. e. Its total displacement is ________________. f. Its average velocity is _________________. |
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Answer» Answer: Initial MOMENTUM = 0 because body is at rest. Final Velocity = 160 m/s Displacement is 4000 m Average Velocity is 120 m/s Explanation: Initial Momentum is 0 because body is at rest. Final Velocity = Vi + at Acceleration = F/m Displacement = VIT + 1/2 at^2 °Vi= 160 m/s a= 4 m/s^2 t= 20 sec Total Displacement = Vit+ 1/2 at^2 ° Vi= 0m/s a= 4m/s^2 t= 60sec Average Velocity = Total Displacement / Total Time |
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