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a force acts for dance on a stationary body of mass 100 kg after which the force accuses to add the body moves through a distance of 100m in next 5 second calculate the velocity acquired by the body the acceleration produced by the body and the magnitude of the body |
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Answer» GIVEN:- Initial VELOCITY = 0m/s. Mass of Body = 100kg Distance Moved = 100m Time = 5s. To Find:- The Velocity acquired by the body the Acceleration produced by the body and the magnitude of the body. FORMULAE USED
Where, v = Final Velocity u = Initial Velocity S = Distance F = Force m = mass a = Acceleration t = Time. Now, Using Second equation of MOTION to find Acceleration. S = ut + ½ × a × t² 100m = 0 + ½ × a × 25 4 = ½ × a a = 8m/s² Hence, The Acceleration is 8m/s². Therefore, Using First equation of motion to find Final Velocity v = u + at v = 0 + 40 v = 40m/s. Thus, The SPEED acquired by body is 40m/s. Hence, Using F = ma to find force. F = ma F = 100 × 8 F = 800N. Thus, The magnitude of Force is 800N |
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