A force F = 10 N acting on a box 1 m along a horizontal surface. The f

1.	A force F = 10 N acting on a box 1 m along a horizontal surface. The force acts at 30° angle. Determine the work done by force the work done force F.
Answer» Explanation: Given :- Force (F) = 10 N The HORIZONTAL force (Fx) = Fcos30° Fx = 10(√3/2) = 5 × 1.73 = 8.65 N Displacement (s) = 1 m ____________________________ To find :- WORK done (W) = ?____________________________ Solution :- We have, Work done (W) = Force × displacement => W = Fx × s => W = 8.65 × 1 => W = 8.65 J _____________________________ The work done is 8.65 J _______________________[ANSWER ]

A force F = 10 N acting on a box 1 m along a horizontal surface. The force acts at 30° angle. Determine the work done by force the work done force F.

Answer»

Explanation:

Given :-

Force (F) = 10 N

The HORIZONTAL force (Fx) = Fcos30°

Fx = 10(√3/2) = 5 × 1.73 = 8.65 N

Displacement (s) = 1 m

____________________________

To find :-

WORK done (W) = ?____________________________

Solution :-

We have,

Work done (W) = Force × displacement

=> W = Fx × s

=> W = 8.65 × 1

=> W = 8.65 J

_____________________________

The work done is 8.65 J

_______________________[ANSWER ]

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A force F = 10 N acting on a box 1 m along a horizontal surface. The force acts at 30° angle. Determine the work done by force the work done force F.​

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A force F = 10 N acting on a box 1 m along a horizontal surface. The force acts at 30° angle. Determine the work done by force the work done force F.