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A force `F` acts tangentially at the highest point of a disc of mass `m` kept on a rough horizontal plane. If the disc rolls without slipping, the acceleration of centre of the disc is: A. `(2F)/(3m)`B. `(10F)/(7m)`C. zeroD. `(4F)/(3m)` |
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Answer» Correct Answer - D `F+f=Ma` ………..i `FR=fR=(MR^(2))/2 a/R`……ii `F-f=(Ma)/w`………..iii `2F=(2Ma)/wimpliesa=(4F)/(3M)` |
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