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A force F = Kx2 acts on a particle at an angle of60° with the x-axis. The work done in displacingthe particle from x, to x2 will be17.thkx222) s236 |
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Answer» We have, dW = F→.dx→ = Fdx cos θ = Fdx cos 60˚ = 1/2Fdx = 1/2Kx^2 Therefore, W = K/2x1∫x2x2dx = K/2[x^3/3]x1x2 = K/6(x2^3– x1^3) thanks but I don't understand |
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