1.

A force F = Kx2 acts on a particle at an angle of60° with the x-axis. The work done in displacingthe particle from x, to x2 will be17.thkx222) s236

Answer»

We have, dW = F→.dx→

= Fdx cos θ

= Fdx cos 60˚

= 1/2Fdx

= 1/2Kx^2

Therefore, W = K/2x1∫x2x2dx

= K/2[x^3/3]x1x2

= K/6(x2^3– x1^3)

thanks but I don't understand



Discussion

No Comment Found

Related InterviewSolutions