A force is acting on a body of mass 0.4 kg intially at rest for 10 sec

1.	A force is acting on a body of mass 0.4 kg intially at rest for 10 sec and after removal of the force the body moves 100m in 20 sec . What was it's intiall force?
Answer» Answer: 0.2 N Explanation: Given : Mass = 0.4 kg In FIRST case : u = 0 m / sec t = 20 sec We have : v = u + a t v = 0 + 20 a v = 20 a . For second case : v become initial velocity : u = 20 a t' = 10 sec s = 100 m We have : s = u t + 1 / 2 a t² 100 = 20 a × 10 + 1 / 2 × a × 10² 1 = 2 a + a / 2 a = 0.5 m / sec² We know : F = m a F = 0.4 × 0.5 N F = 0.2 N

A force is acting on a body of mass 0.4 kg intially at rest for 10 sec and after removal of the force the body moves 100m in 20 sec . What was it's intiall force?

Answer»

Answer:

0.2 N

Explanation:

Given :

Mass = 0.4 kg

In FIRST case :

u = 0 m / sec

t = 20 sec

We have :

v = u + a t

v = 0 + 20 a

v = 20 a .

For second case :

v become initial velocity :

u = 20 a

t' = 10 sec

s = 100 m

We have :

s = u t + 1 / 2 a t²

100 = 20 a × 10 + 1 / 2 × a × 10²

1 = 2 a + a / 2

a = 0.5 m / sec²

We know :

F = m a

F = 0.4 × 0.5 N

F = 0.2 N

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