A force of 100 N gives a mass m1, an acceleration of 10"ms"^(-2) "and of 20ms"^(-2) to a mass m^2. What acceleration must be given to it if both the masses are tied together ?

A force of 100 N gives a mass m1, an acceleration of 10"ms"^(-2) "and

1.	A force of 100 N gives a mass m1, an acceleration of 10"ms"^(-2) "and of 20ms"^(-2) to a mass m^2. What acceleration must be given to it if both the masses are tied together ?
Answer» Solution :Suppose, a= acceleration PRODUCED if `m_1 and m_2` are tied TOGETHER, F= 100 N Let `a_1 and a_2` be the acceleration produced in `m_1 and m_2,` RESPECTIVELY. `a_(1)=10ms^(-2), a_(2)=20ms^(-2)("given")` Again `m_(1)=F/a_(1) and m_(2)=F/a_(2)` `rArr m_(1)=(100)/(10)=10ms^(-2)` `and m_(2)=(100)/(20)=5 ms^(-2)` `therefore m_(1)+m_(2)=10+5=15` So, `a=(F)/(m_(1)+m_(2))=(100)/(15)=(20)/(3)` `=6.67 ms^(-2)`