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A force of 20N acts on a surface of area 2m^2 another force of 5N acts on same surface. Calculate the pressure in each case. |
Answer» <html><body><a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> in first case is 10pascals and pressure in the <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> case is 2.5pascalsExplanation:as pressure is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> <a href="https://interviewquestions.tuteehub.com/tag/divided-441039" style="font-weight:bold;" target="_blank" title="Click to know more about DIVIDED">DIVIDED</a> by areaso , pressure in first case=20÷2=10pascals pressure in second case=5÷2=2.5pascals</body></html> | |