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A force of `50N` is inclined to the vertical at an angle of `30^(@)` Find the acceleration it produes in a body of mass `2kg` which moves in the horizontal direction . |
Answer» Correct Answer - `12.5m//s^(2)` Here, `F = 50N` angle with verticle `0 = 30^(@)` In the horizontal direction, `a = ("horizontal force")/("mass") = (F sin0)/(m) = (50sin30^(@))/(2)` `=12.5 m//s^(2)` . |
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