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A force of `5N` gives a mass `m_(1)`, an acceleration of `8 m//s^(2)`, and a mass `m_(2)`, an acceleration of `24 m//s^(2)`. What acceleration would it give if both the masses are tied together? |
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Answer» (i) In the first case: Force, F=5 N Mass,m=`m_(1)` (To be calculated) And, Acceleration, a = 8 m/`s^(2)` Now, F=`mxxa` So, `5=m_(1)xx8` And, `m_(1)=5/8kg` `m_(1)=0.625kg` Thus, the mass `m_(1)` is 0.625 kg. (ii) In the second case: Force, F = 5 N Mass, m=`m_(2)` (To be calculated) And, Acceleration a=24 m/`s^(2)` Now, F=m`xx`a So, `5=m_(2)xx24` And, `m_(2)=5/24kg` `m_(2)=0.208` kg Thus, the mass m2 is 0.208 kg. (iii) In the third case: Force=5N Total mass, m = `m_(1)+m_(2)`. =0.625+0.208 =0.833 kg And, Acceleration, a = ? (To be calculated) Now putting these values in the relation : `F=mxxa` We get : `5=0.833xxa` `a=5/0.833` `a=6 m//s^(2)` Thus, if both the masses are tied together, then the acceleration would be 6 m/`s^(2)` |
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