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A hammer of mass `500g`, moving at `50m//s`, strikes a nail. The nail stops the hammer in a very short time of `0.01 s`. What is the force of the nail on the hammer? |
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Answer» Here, Mass,m=500 g `=500/1000Kg` =0.5 kg We will now calculate the acceleration. Now, Initial velocity,`u=50 m1s^(-1)` Final velocity,v = 0 (The hammer stops) Acceleration, a= ? (To be calculated) And, Time,t=0.01 s Now, v=u+at So, `0=50+axx0.01` 0.01a=-50 `a=-50/0.01` `a=-5000ms^(-2)` We know that : Force,F=m`xx`a So, `F=0.5xx(-5000)N` F=-2500 N Thus, the force of the nail on the hammer is 2500 newtons. The negative sign indicates that this force is opposing motion. |
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