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A free alpha particle and a free proton are separated by distance of 10 particle when at infinite separation is m and are released. The kinetic energy of alpha Options: -19 28.6 x 10 J-19 9.2 x 10 J -19 36.8 x 10 J -19 12.5 x 10 J​

Answer»

energy of both α-PARTICLE and PROTON= Potential energy of two particles(2e)(E) / 4πε0r=2×(1.6×10−19)2×9×109 / 10−10= 46.08×10−19As initial momentum of two particles is zero, their final momentum must also be zero.= NUMERICAL value of momentum of each particle = p.KE of proton = p²/ 2m=E(say)Kinetic energy of α-particle =p2²/ (4m)=E4Total kinetic energy = E+ E/ 4=46.08×10−19J= E=4/ 5×46×10−19J=36.8×10−19Jhence, KE of α-particle = 36.8×10−19 / 4=29.2×10−19Jplease MARK me brain mark list


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