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A gas `(C_(v.m) = (5)/(2)R)` behaving ideally is allowed to expand reversibly and adiabatically from `1` litre to `32` litre. Its initial temperature is `327^(@)C`. The molar enthalpy change (in `J//mol`) for the process is :A. `-1125 R`B. `-675`C. `-1575 R`D. 101 R |
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Answer» Correct Answer - C `(T_(2))/(T_(1)) = ((V_(1))/(V_(2)))^(gamma-1), T_(2) = T_(1)((1)/(32))^((7)/(5)-1) = 600((1)/(2^(5)))^(2//5)` `= 600(0.5)^(2)=150K, Delta H_(m) = (7)/(2)R xx(150-600) = -1575 R` |
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