1.

A gas expands by `0.372` litre against a constant pressure of `1atm`. Find the work done in cal.

Answer» Correct Answer - 9
`W=-P_(ext)xxDeltaV`
`=-1xx0.372=-0.372` litre-atm
`0.372` litre atm`=-0.372xx1.987/0.0821~~-9.0 cal`


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