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A gas expands by `0.372` litre against a constant pressure of `1atm`. Find the work done in cal. |
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Answer» Correct Answer - 9 `W=-P_(ext)xxDeltaV` `=-1xx0.372=-0.372` litre-atm `0.372` litre atm`=-0.372xx1.987/0.0821~~-9.0 cal` |
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