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A gas expands from a volume of 1`m^(3)` to a volume of`2m^(3)` against an external pressure of`10^(5) Nm^(-2)`. The work done by the gas will beA. `10^(5) kJ `B. ` 10^(2) kJ`C. ` 10^(2) J`D. `10^(3)J` |
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Answer» Correct Answer - b `w = - PDeltaV = - 10^(5) Nm^(-2) ( 2-1) m^(3) = - 10^(5) Nm = - 10^(5) J = -10^(2) kJ ` |
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