InterviewSolution
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InterviewSolution
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A gas expands with temperature according to the relation `V=KT^(2/3)`.Work done when the temperature changes by 60K is.A. 10RB. 30RC. 40RD. 20R |
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Answer» Correct Answer - C Here dW =PdV=`(RT)/(V)dV` Given `V=KT^(2//3)` therefore `dV=K(2)/(3)(dT)/(T)` From (i) `W=overset(T_(2))underset(T_(1))int RT (dV)/(V)=overset(T_(2))underset(T_(1))int RT(2)/(3) (dT)/(T)` `W=(2)/(3)R(T_(2)-T_(1))=(2)/(3)Rxx60 =40R` |
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