A geostationary satellite is orbiting the earth at a height of 4R above the earth’s surface. The time period of another satellite at a height of 2R is _____(a) 24 x (3/5)^1/2 hr(b) 12 x (3/5)^1/2 hr(c) 6 x (3/5)^1/2 hr(d) 72 x (3/5)^1/21 hrThe question was asked during an interview for a job.I'd like to ask this question from Gravitation in section Gravitation of Physics – Class 11

A geostationary satellite is orbiting the earth at a height of 4R abov

1.	A geostationary satellite is orbiting the earth at a height of 4R above the earth’s surface. The time period of another satellite at a height of 2R is _____(a) 24 x (3/5)^1/2 hr(b) 12 x (3/5)^1/2 hr(c) 6 x (3/5)^1/2 hr(d) 72 x (3/5)^1/21 hrThe question was asked during an interview for a job.I'd like to ask this question from Gravitation in section Gravitation of Physics – Class 11
Answer» Correct CHOICE is (a) 24 x (3/5)^1/2 hr Easiest explanation: The time PERIOD of a satellite is given by; T = 2 x pi x (R+h)^3/2 / (G x M)^1/2 For a geostationary satellite; 24 = (5R)^3/2 x (constant); [As per GIVER information] Required; t = (3R)^2/2 x (constant) t = Time period of the satellite at a height of 2.5R t/24 = (3R/5R)^3/2 = (3/5)^3/2 t = 24 x (3/5)^1/2 hr.

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