A geostationary satellite is orbiting the Earth at a height of `6 R` above the surface of Earth, where `R` is the radius of the Earth. The time period of another satellites is `6 sqrt(2) h`. Find its height from the surface of Earth.

A geostationary satellite is orbiting the Earth at a height of `6 R` a

1.	A geostationary satellite is orbiting the Earth at a height of `6 R` above the surface of Earth, where `R` is the radius of the Earth. The time period of another satellites is `6 sqrt(2) h`. Find its height from the surface of Earth.
Answer» Here, `r_(1) = 6R + R = 7 R, T_(1) = 24 h, T_(2) = 6 sqrt(2) h`, `r_(2) = r_(1) ((r_(2))/(r_(1)))^(3//2) = 7R((6sqrt(2))/(24))^(2//3) = 7R((1)/(2)) = 3.5 R` `:.` Height of satellite from the surface of earth `= 3.5 R - R` `= 2.5 R`

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A geostationary satellite is orbiting the Earth at a height of `6 R` above the surface of Earth, where `R` is the radius of the Earth. The time period of another satellites is `6 sqrt(2) h`. Find its height from the surface of Earth.

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