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A satellite revolves in an orbit close to the surface of a planet of mean density `5.51 xx 10^(3) kg m^(-3)`. Calculate the time period of satellite. Given `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`. |
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Answer» `T = (2pi R)/(upsilon_(0)) = (2pi R)/(sqrt(GM//R)) = (2pi R)/(sqrt((G)/(R ) xx (4)/(3) pi R^(2) rho))` `= 2 sqrt((3pi)/(4G rho))` `:. T = 2 sqrt((3 xx 22)/(7 xx 4 xx 6.67 xx 10^(-11) xx 5.5 xx 10^(3)))` `= 5065 s` |
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