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Escape velocity of a body `1 kg` mass on a planet is `100 ms^(-1)`. Gravitational potential energy of the body at that planet isA. `-5000 J`B. `-1000 J`C. `-2400 J`D. `5000 J` |
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Answer» Correct Answer - A `upsilon_(e) = sqrt((2GM)/(R )) = 100 ms^(-1)` or `(GM)/(R ) = ((100)^(2))/(2) = 5000` `P.E., U = - (GM)/(R ) = - 5000 J` |
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