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A geyser heats water flowing at a rate of 3.0 litres per minute from 27°C to 77°C. If geyser operates on a gas burner, what is the rate consumption of the fuel if the heat of combustion is 4. 0 × 104 J/g |
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Answer» Rate of flow of water = 3 litres/minute ∴ Mass of water flowing per minute, M = 3000g / minute Initial temperature, T1 = 27°C Final temperature, T2= 77°C Rise in temperature of the flowing water ∆ T = T2 – T1 = (77 – 27)° C = 50° C specific heat of water, c = 4200 J kg-1 °C-1 = 4.2 Jg-1 °C-1 ∴ Total heat supplied by geyser, ∆ Q = mc ∆T = 3000 × 4.2 × 50 = 630000 J/min = 6.3 × 105 J/min Heat of combustion of geyser = 4 × 104Jg-1 ∴ Rate of consumption of fuel, r = \(\frac{6.3 \times 10^5}{4.0 \times 10^4}\) = 15. 75 g/min. |
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