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A girl walks 4 km towards west, then she walks 3 km in a direction `30o`east of north and stops. Determine the girls displacement from her initial point of departure. |
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Answer» `veca=4(-hati)km` `vecb=3(sin30^ohati+cos30^ohatj)km` =`3(1/2hati+sqrt3/2hatj)` =`(3/2hati+(3sqrt3)/2hatj)` distance between them =`veca+vecb` =`-4hati+3/2hati+(3sqrt3)/2hatj` =`-5/2hati+(3sqrt3)/3hatj` |
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