1.

A girl walks 4 km towards west, then she walks 3 km in a direction `30o`east of north and stops. Determine the girls displacement from her initial point of departure.

Answer» `veca=4(-hati)km`
`vecb=3(sin30^ohati+cos30^ohatj)km`
=`3(1/2hati+sqrt3/2hatj)`
=`(3/2hati+(3sqrt3)/2hatj)`
distance between them
=`veca+vecb`
=`-4hati+3/2hati+(3sqrt3)/2hatj`
=`-5/2hati+(3sqrt3)/3hatj`


Discussion

No Comment Found

Related InterviewSolutions