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A given sample of milk turns sour at room temperature `(27^(@)C)` in five hours. In a refrigerator at `-3^(@)C`, it can be stored 10 times longer. The energy of acrivation for the souring of milk isA. `2.303xx5RkJ" mol"^(-1)`B. `2.303xx3RkJ" mol"^(-1)`C. `2.303xx2.7RkJ" mol"^(-1)`D. `2.303xx10RkJ" mol"^(-1)` |
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Answer» Correct Answer - C Energy of activation is given by `"log"(k_(2))/(k_(1))=E_(a)/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]` `Here, (k_(2))/(k_(1))=(1)/(10),T_(1)=27^@C=300k,T_(2)=-3^@C=270k` `therefore" log"(1)/(10)=E_(a)/(2.303R)[(270-300)/(270xx300)]` `-1=-E_(a)/(2.303R)((30)/(270xx300))` `E_(a)=+2.303xx2700xxRJ" mol"^(-1)` `=+2.303xx2.7xxRkJ" mol"^(-1)` |
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