1.

A graph between the square of the velocity of a particle and the distance(s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is:- A. 2250B. 3084C. -2250D. -3084

Answer» Correct Answer - D
`V^(2)=U^(2)+2as`
`a=(v^(2)-u^(2))/(2s)=((900)-(4600))/(2xx0.6)=-(3700)/(1.2)`
`=-3084 km//hr^(2)`


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