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A graph between the square of the velocity of a particle and the distance(s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is:- A. 2250B. 3084C. -2250D. -3084 |
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Answer» Correct Answer - D `V^(2)=U^(2)+2as` `a=(v^(2)-u^(2))/(2s)=((900)-(4600))/(2xx0.6)=-(3700)/(1.2)` `=-3084 km//hr^(2)` |
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