A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding that stops the hammer .

A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall

1.	A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding that stops the hammer .
Answer» (i) Impulse =`Fxxt`=m(v-u)=1(0-6)=-6 Ns (ii) Average retarding force that stops the hammer `F=("Impulse")/("Time")=(6)/(0.1)`=60 N (iii) Average retardation, `a=(F)/(m)=(60)/(1)=60ms^(-2)`

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A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding that stops the hammer .

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