InterviewSolution
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InterviewSolution
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A healthy youngman standing at a distance of 7 m from 11.8 m high building sees a kid slipping from the top floor. With what speed (assumed uniform) should he run to catch the kid at the arms hieght (1.8m)? |
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Answer» Correct Answer - A::B::D At point B (i.e. over 1.8 m from ground), the kid should be caught. For kid: Initial velocity `u=0` Acceleration = 9.8 m/s^2 Distance S= 11.8-1.8=10 m No S= ut+ 1/2 `at^2` 10=0+ 1/2 (9.8)`t^2` ` t^2`= 10/4.9=2.04 t= 1.42 `` In this time the man has to reach at the bottom of the building `:. Velocity =S/t=7/1.42= 4.9 m/s` |
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