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A particle starting from rest moves with constant acceleration. If it takes 5.0 s to reash the speed 18.0 km/h find a. the average velocity during this period, and b. the distance travelled by the particle during this period. |
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Answer» Correct Answer - A::B Given, `u=0 v=18km/hr =5m/s t=5 sec a=v-ut =5-0xx5 =5m/s^2 S=ut+1/2at^2ltbrge1/2xx1xx(5xx5) =12.5m a. Average velocity V_(ve)=(12.5)/5 =2.5 m/s b. Distance travelled = 12.5 m`. |
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