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A person travelling at 43.2 km/h applies the brake giving a deceleration of `6.0 m/ss^2` to his scooter. How far will it travel before stopping? |
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Answer» Correct Answer - A::B Initial velocity `u=43.2 km/hr= 12 m/s u=12 m/s v=0 a=6m/s^2 (Deceleration) Distance S= (v^2-u^2)/(2(-a)) =(0-(12)^2)/(2)-6)) =(12xx12)/12=12m` |
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