A heat engine (efficiency=40%) does 20 kJ of mechanical work. How much is the heat supplied to this engine in calories?

A heat engine (efficiency=40%) does 20 kJ of mechanical work. How much

1.	A heat engine (efficiency=40%) does 20 kJ of mechanical work. How much is the heat supplied to this engine in calories?
Answer» EFFICIENCY = 40% $\eta= \frac{work\ done}{<klux>HEAT</klux>\ <klux>SUPPLIED</klux>}\\ \\ \Rightarrow 0.4= \frac{20\ kJ}{Heat\ supplied} \\ \\ \Rightarrow Heat\ Supplied= \frac{20}{0.4} =50\ kJ$ $1\ calorie = 4.184\ J\\50 kJ = \frac{50}{4.184}\ <klux>KCAL</klux>=11.95\ kcal$ So 11.95 kcal heat should be supplied.

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A heat engine (efficiency=40%) does 20 kJ of mechanical work. How much is the heat supplied to this engine in calories?

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