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A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass is M. It suspended by a string in a liquid of density `rho` where it stays vertical. The upper surface of cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder bby the liquid is A. MgB. Mg - h `rho` gC. `Mg + pi R^(2)h rho g`D. `rho g(V+pi R^(2)h)` |
Answer» Correct Answer - D The net upward force on the bottom of cylinder = wt. of liquid displaced by cylinder + thrust on the upper surface of cylinder due to h column of lliquid. `V rho g+h rho gxxpi R^(2)` `=rho g(V+pi R^(2)h)` |
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