1.

A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass M. It is suspended by a string in a liquid of density `rho` where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder by the liquid is

Answer» Buoyant force on the cylinder = weight of liquid displaced = `V rho g`
downward force on the top of cylinder
` =(h rho g) pi R^(2)`
Force on the bottom of cylinder is
`F =` Bouyant force + downward force on the top of cylinder
`=V rho g +(h rho g) pi R^(2) = rho g (V + pi R^(2)h)`.


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