InterviewSolution
Saved Bookmarks
| 1. |
A hunter has a machine gun that can fire 50 g bullets with a velocity of `150 m//s` . A 60 kg tiger springs at him with a velocity of `10 ms^(-1)` How many bullets must the hunter fire per secoud into the tiger in order to stop him in his track. |
|
Answer» Here, ` m = 50 g = 50 xx 10^(-3) kg ` ` upsilon = 150 m//s , M =60 kg V = 10 m//s ` ` n= ` ? According to the principal of conservation of linear momentum , change in momentum of bullets = change in momentum of tiger ` nxx m xx upsilon = MV ` ` n = (MV)/(mxxupsilon )=(60xx10)/(50 xx 10^(-3) xx 150 ` ` n = 80` (bullet/sec). |
|