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A hypothetical reaction `A_(2) + B_(2) rarr 2AB` follows the mechanism as given below: `A_(2) hArr A+A ("fast")` `A+B_(2) rarr AB+B` (slow) `A+B rarr AB` (fast) The order of the overall reaction isA. `2`B. `1`C. `3//2`D. Zero |
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Answer» Correct Answer - c `r=K[A][B_(2)]` and `K_(c )=([A][A])/([A_(2)])` or `[A]=K_(c )^(1//2)[A_(2)]^(1//2)` Thus `r=K.K_(c )^(1//2)[A_(2)]^(1//2)[B_(2)]` `=K^(1)[A_(2)]^(1//2)[B_(2)]` or order is `3//2`. |
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